101134230111333 has 24 divisors (see below), whose sum is σ = 147046792353240. Its totient is φ = 66978875289600.

The previous prime is 101134230111301. The next prime is 101134230111337. The reversal of 101134230111333 is 333111032431101.

101134230111333 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 342 + 301 + 1 + 13 + 3 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 6563136907044 + 94571093204289 = 2561862^2 + 9724767^2 .

It is not a de Polignac number, because 101134230111333 - 2⁵ = 101134230111301 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101134230111297 and 101134230111306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101134230111337) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39828768 + ... + 42291833.

It is an arithmetic number, because the mean of its divisors is an integer number (6126949681385).

Almost surely, 2^{101134230111333} is an apocalyptic number.

It is an amenable number.

101134230111333 is a deficient number, since it is larger than the sum of its proper divisors (45912562241907).

101134230111333 is a wasteful number, since it uses less digits than its factorization.

101134230111333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82121509 (or 82121506 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 27.

Adding to 101134230111333 its reverse (333111032431101), we get a palindrome (434245262542434).

The spelling of 101134230111333 in words is "one hundred one trillion, one hundred thirty-four billion, two hundred thirty million, one hundred eleven thousand, three hundred thirty-three".