10113434301 has 4 divisors (see below), whose sum is σ = 13484579072. Its totient is φ = 6742289532.

The previous prime is 10113434293. The next prime is 10113434333. The reversal of 10113434301 is 10343431101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10113434301 - 2³ = 10113434293 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113434501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685572381 + ... + 1685572386.

It is an arithmetic number, because the mean of its divisors is an integer number (3371144768).

Almost surely, 2^10113434301 is an apocalyptic number.

It is an amenable number.

10113434301 is a deficient number, since it is larger than the sum of its proper divisors (3371144771).

10113434301 is an equidigital number, since it uses as much as digits as its factorization.

10113434301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3371144770.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10113434301 its reverse (10343431101), we get a palindrome (20456865402).

It can be divided in two parts, 10 and 113434301, that added together give a palindrome (113434311).

The spelling of 10113434301 in words is "ten billion, one hundred thirteen million, four hundred thirty-four thousand, three hundred one".