1011344332001 has 2 divisors, whose sum is σ = 1011344332002. Its totient is φ = 1011344332000.

The previous prime is 1011344331997. The next prime is 1011344332013. The reversal of 1011344332001 is 1002334431101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1010425029601 + 919302400 = 1005199^2 + 30320^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011344332001 - 2² = 1011344331997 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011344332081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505672166000 + 505672166001.

It is an arithmetic number, because the mean of its divisors is an integer number (505672166001).

Almost surely, 2^{1011344332001} is an apocalyptic number.

It is an amenable number.

1011344332001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011344332001 is an equidigital number, since it uses as much as digits as its factorization.

1011344332001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1011344332001 its reverse (1002334431101), we get a palindrome (2013678763102).

The spelling of 1011344332001 in words is "one trillion, eleven billion, three hundred forty-four million, three hundred thirty-two thousand, one".