10113525412411 has 2 divisors, whose sum is σ = 10113525412412. Its totient is φ = 10113525412410.

The previous prime is 10113525412381. The next prime is 10113525412421. The reversal of 10113525412411 is 11421452531101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10113525412411 - 2¹³ = 10113525404219 is a prime.

It is a super-3 number, since 3×10113525412411³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10113525412421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056762706205 + 5056762706206.

It is an arithmetic number, because the mean of its divisors is an integer number (5056762706206).

Almost surely, 2^{10113525412411} is an apocalyptic number.

10113525412411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113525412411 is an equidigital number, since it uses as much as digits as its factorization.

10113525412411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 10113525412411 its reverse (11421452531101), we get a palindrome (21534977943512).

The spelling of 10113525412411 in words is "ten trillion, one hundred thirteen billion, five hundred twenty-five million, four hundred twelve thousand, four hundred eleven".