10114000423 has 4 divisors (see below), whose sum is σ = 10252548448. Its totient is φ = 9975452400.

The previous prime is 10114000399. The next prime is 10114000439. The reversal of 10114000423 is 32400041101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10114000423 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10114000397 and 10114000406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114000493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69273903 + ... + 69274048.

It is an arithmetic number, because the mean of its divisors is an integer number (2563137112).

Almost surely, 2^10114000423 is an apocalyptic number.

10114000423 is a deficient number, since it is larger than the sum of its proper divisors (138548025).

10114000423 is an equidigital number, since it uses as much as digits as its factorization.

10114000423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138548024.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 10114000423 its reverse (32400041101), we get a palindrome (42514041524).

The spelling of 10114000423 in words is "ten billion, one hundred fourteen million, four hundred twenty-three", and thus it is an aban number.