Base | Representation |
---|---|
bin | 11101011011111001110… |
… | …10110011011001110001 |
3 | 10120200122010012012012112 |
4 | 32231330322303121301 |
5 | 113032333223313431 |
6 | 2052345312535105 |
7 | 133033521352301 |
oct | 16557472633161 |
9 | 3520563165175 |
10 | 1011413104241 |
11 | 35aa3536a051 |
12 | 144028251495 |
13 | 744b6972267 |
14 | 36d4a12d601 |
15 | 1b498706c2b |
hex | eb7ceb3671 |
1011413104241 has 2 divisors, whose sum is σ = 1011413104242. Its totient is φ = 1011413104240.
The previous prime is 1011413104213. The next prime is 1011413104291. The reversal of 1011413104241 is 1424013141101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 564119664241 + 447293440000 = 751079^2 + 668800^2 .
It is an emirp because it is prime and its reverse (1424013141101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011413104241 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011413104291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505706552120 + 505706552121.
It is an arithmetic number, because the mean of its divisors is an integer number (505706552121).
Almost surely, 21011413104241 is an apocalyptic number.
It is an amenable number.
1011413104241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011413104241 is an equidigital number, since it uses as much as digits as its factorization.
1011413104241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1011413104241 its reverse (1424013141101), we get a palindrome (2435426245342).
The spelling of 1011413104241 in words is "one trillion, eleven billion, four hundred thirteen million, one hundred four thousand, two hundred forty-one".
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