Base | Representation |
---|---|
bin | 10010110101101101… |
… | …01010010111001001 |
3 | 222002212200021100101 |
4 | 21122312222113021 |
5 | 131203214311241 |
6 | 4351342405401 |
7 | 505432252252 |
oct | 113266522711 |
9 | 28085607311 |
10 | 10114213321 |
11 | 4320234193 |
12 | 1b63290861 |
13 | c52569514 |
14 | 6bd3b3b29 |
15 | 3e2e1de31 |
hex | 25adaa5c9 |
10114213321 has 2 divisors, whose sum is σ = 10114213322. Its totient is φ = 10114213320.
The previous prime is 10114213301. The next prime is 10114213349. The reversal of 10114213321 is 12331241101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7948614025 + 2165599296 = 89155^2 + 46536^2 .
It is a cyclic number.
It is not a de Polignac number, because 10114213321 - 217 = 10114082249 is a prime.
It is a super-2 number, since 2×101142133212 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10114213301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057106660 + 5057106661.
It is an arithmetic number, because the mean of its divisors is an integer number (5057106661).
Almost surely, 210114213321 is an apocalyptic number.
It is an amenable number.
10114213321 is a deficient number, since it is larger than the sum of its proper divisors (1).
10114213321 is an equidigital number, since it uses as much as digits as its factorization.
10114213321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 10114213321 its reverse (12331241101), we get a palindrome (22445454422).
The spelling of 10114213321 in words is "ten billion, one hundred fourteen million, two hundred thirteen thousand, three hundred twenty-one".
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