Base | Representation |
---|---|
bin | 1001001100101110011110… |
… | …1111111011001110101111 |
3 | 1022210220121212001012022211 |
4 | 2103023213233323032233 |
5 | 2311202431211140210 |
6 | 33302230200351251 |
7 | 2062505215656550 |
oct | 223134757731657 |
9 | 38726555035284 |
10 | 10114241115055 |
11 | 324a4754826a0 |
12 | 117425aa75527 |
13 | 5849cc1c835c |
14 | 26d7636ac327 |
15 | 12816453c38a |
hex | 932e7bfb3af |
10114241115055 has 32 divisors (see below), whose sum is σ = 15323499325440. Its totient is φ = 6225171563520.
The previous prime is 10114241115049. The next prime is 10114241115067. The reversal of 10114241115055 is 55051114241101.
It is not a de Polignac number, because 10114241115055 - 23 = 10114241115047 is a prime.
It is a super-4 number, since 4×101142411150554 (a number of 53 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 166240194 + ... + 166301023.
It is an arithmetic number, because the mean of its divisors is an integer number (478859353920).
Almost surely, 210114241115055 is an apocalyptic number.
10114241115055 is a deficient number, since it is larger than the sum of its proper divisors (5209258210385).
10114241115055 is a wasteful number, since it uses less digits than its factorization.
10114241115055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 332541319.
The product of its (nonzero) digits is 4000, while the sum is 31.
Adding to 10114241115055 its reverse (55051114241101), we get a palindrome (65165355356156).
The spelling of 10114241115055 in words is "ten trillion, one hundred fourteen billion, two hundred forty-one million, one hundred fifteen thousand, fifty-five".
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