101143132404442 has 4 divisors (see below), whose sum is σ = 151714698606666. Its totient is φ = 50571566202220.

The previous prime is 101143132404427. The next prime is 101143132404463. The reversal of 101143132404442 is 244404231341101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 97626078509281 + 3517053895161 = 9880591^2 + 1875381^2 .

It is a super-2 number, since 2×101143132404442² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101143132404398 and 101143132404407.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25285783101109 + ... + 25285783101112.

Almost surely, 2^{101143132404442} is an apocalyptic number.

101143132404442 is a deficient number, since it is larger than the sum of its proper divisors (50571566202224).

101143132404442 is an equidigital number, since it uses as much as digits as its factorization.

101143132404442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50571566202223.

The product of its (nonzero) digits is 36864, while the sum is 34.

Adding to 101143132404442 its reverse (244404231341101), we get a palindrome (345547363745543).

The spelling of 101143132404442 in words is "one hundred one trillion, one hundred forty-three billion, one hundred thirty-two million, four hundred four thousand, four hundred forty-two".