101144021131341 has 48 divisors (see below), whose sum is σ = 149397559234560. Its totient is φ = 65909708117280.

The previous prime is 101144021131319. The next prime is 101144021131357. The reversal of 101144021131341 is 143131120441101.

101144021131341 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 440 + 211 + 3 + 1 + 3 + 4 + 1 = 666.

It is not a de Polignac number, because 101144021131341 - 2⁷ = 101144021131213 is a prime.

It is a super-2 number, since 2×101144021131341² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101144021141341) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1634514240 + ... + 1634576118.

It is an arithmetic number, because the mean of its divisors is an integer number (3112449150720).

Almost surely, 2^{101144021131341} is an apocalyptic number.

It is an amenable number.

101144021131341 is a deficient number, since it is larger than the sum of its proper divisors (48253538103219).

101144021131341 is a wasteful number, since it uses less digits than its factorization.

101144021131341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66846 (or 66843 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 101144021131341 its reverse (143131120441101), we get a palindrome (244275141572442).

The spelling of 101144021131341 in words is "one hundred one trillion, one hundred forty-four billion, twenty-one million, one hundred thirty-one thousand, three hundred forty-one".