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10115102057 is a prime number
BaseRepresentation
bin10010110101110100…
…00011010101101001
3222002221100102110112
421122322003111221
5131203431231212
64351413424105
7505442643314
oct113272032551
928087312415
1010115102057
114320790985
121b6363b035
13c527babb8
146bd56597b
153e3047422
hex25ae83569

10115102057 has 2 divisors, whose sum is σ = 10115102058. Its totient is φ = 10115102056.

The previous prime is 10115101999. The next prime is 10115102089. The reversal of 10115102057 is 75020151101.

10115102057 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10106481961 + 8620096 = 100531^2 + 2936^2 .

It is a cyclic number.

It is not a de Polignac number, because 10115102057 - 212 = 10115097961 is a prime.

It is not a weakly prime, because it can be changed into another prime (10115102857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057551028 + 5057551029.

It is an arithmetic number, because the mean of its divisors is an integer number (5057551029).

Almost surely, 210115102057 is an apocalyptic number.

It is an amenable number.

10115102057 is a deficient number, since it is larger than the sum of its proper divisors (1).

10115102057 is an equidigital number, since it uses as much as digits as its factorization.

10115102057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 350, while the sum is 23.

Adding to 10115102057 its reverse (75020151101), we get a palindrome (85135253158).

The spelling of 10115102057 in words is "ten billion, one hundred fifteen million, one hundred two thousand, fifty-seven".