Base | Representation |
---|---|
bin | 1001001100110010100000… |
… | …1000101101001101011011 |
3 | 1022211000102010200222021111 |
4 | 2103030220020231031123 |
5 | 2311212134231244201 |
6 | 33302525305521151 |
7 | 2062544043564505 |
oct | 223145010551533 |
9 | 38730363628244 |
10 | 10115321353051 |
11 | 324a97a21a472 |
12 | 11745007a31b7 |
13 | 584b41c4a035 |
14 | 26d826d44d75 |
15 | 1281c92bcb51 |
hex | 9332822d35b |
10115321353051 has 2 divisors, whose sum is σ = 10115321353052. Its totient is φ = 10115321353050.
The previous prime is 10115321353043. The next prime is 10115321353069. The reversal of 10115321353051 is 15035312351101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10115321353051 - 23 = 10115321353043 is a prime.
It is not a weakly prime, because it can be changed into another prime (10115321353031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057660676525 + 5057660676526.
It is an arithmetic number, because the mean of its divisors is an integer number (5057660676526).
Almost surely, 210115321353051 is an apocalyptic number.
10115321353051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10115321353051 is an equidigital number, since it uses as much as digits as its factorization.
10115321353051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6750, while the sum is 31.
The spelling of 10115321353051 in words is "ten trillion, one hundred fifteen billion, three hundred twenty-one million, three hundred fifty-three thousand, fifty-one".
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