10115412021131 has 2 divisors, whose sum is σ = 10115412021132. Its totient is φ = 10115412021130.

The previous prime is 10115412021119. The next prime is 10115412021149. The reversal of 10115412021131 is 13112021451101.

10115412021131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10115412021131 is a prime.

It is a super-2 number, since 2×10115412021131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10115412021097 and 10115412021106.

It is not a weakly prime, because it can be changed into another prime (10115412021931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057706010565 + 5057706010566.

It is an arithmetic number, because the mean of its divisors is an integer number (5057706010566).

Almost surely, 2^{10115412021131} is an apocalyptic number.

10115412021131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10115412021131 is an equidigital number, since it uses as much as digits as its factorization.

10115412021131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 10115412021131 its reverse (13112021451101), we get a palindrome (23227433472232).

The spelling of 10115412021131 in words is "ten trillion, one hundred fifteen billion, four hundred twelve million, twenty-one thousand, one hundred thirty-one".