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1011683150953 is a prime number
BaseRepresentation
bin11101011100011010000…
…00111100110001101001
310120201022221022222122121
432232031000330301221
5113033411341312303
62052432200551241
7133043310616426
oct16561500746151
93521287288577
101011683150953
11360063845152
121440a2782521
137452a8b3407
1436d73d46d4d
151b4b229a9bd
hexeb8d03cc69

1011683150953 has 2 divisors, whose sum is σ = 1011683150954. Its totient is φ = 1011683150952.

The previous prime is 1011683150921. The next prime is 1011683150957. The reversal of 1011683150953 is 3590513861101.

1011683150953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 646242347664 + 365440803289 = 803892^2 + 604517^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011683150953 - 25 = 1011683150921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011683150957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505841575476 + 505841575477.

It is an arithmetic number, because the mean of its divisors is an integer number (505841575477).

Almost surely, 21011683150953 is an apocalyptic number.

It is an amenable number.

1011683150953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011683150953 is an equidigital number, since it uses as much as digits as its factorization.

1011683150953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 43.

The spelling of 1011683150953 in words is "one trillion, eleven billion, six hundred eighty-three million, one hundred fifty thousand, nine hundred fifty-three".