1011953268481 has 2 divisors, whose sum is σ = 1011953268482. Its totient is φ = 1011953268480.

The previous prime is 1011953268461. The next prime is 1011953268503. The reversal of 1011953268481 is 1848623591101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 781208499600 + 230744768881 = 883860^2 + 480359^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011953268481 - 2¹³ = 1011953260289 is a prime.

It is a super-2 number, since 2×1011953268481² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011953268401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505976634240 + 505976634241.

It is an arithmetic number, because the mean of its divisors is an integer number (505976634241).

Almost surely, 2^{1011953268481} is an apocalyptic number.

It is an amenable number.

1011953268481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011953268481 is an equidigital number, since it uses as much as digits as its factorization.

1011953268481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 49.

The spelling of 1011953268481 in words is "one trillion, eleven billion, nine hundred fifty-three million, two hundred sixty-eight thousand, four hundred eighty-one".