1012000111 has 4 divisors (see below), whose sum is σ = 1012339224. Its totient is φ = 1011661000.

The previous prime is 1012000109. The next prime is 1012000117. The reversal of 1012000111 is 1110002101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1110002101 = 13 ⋅85384777.

It is a cyclic number.

It is not a de Polignac number, because 1012000111 - 2¹ = 1012000109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012000094 and 1012000103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012000117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165040 + ... + 171061.

It is an arithmetic number, because the mean of its divisors is an integer number (253084806).

Almost surely, 2^1012000111 is an apocalyptic number.

1012000111 is a deficient number, since it is larger than the sum of its proper divisors (339113).

1012000111 is an equidigital number, since it uses as much as digits as its factorization.

1012000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339112.

The product of its (nonzero) digits is 2, while the sum is 7.

The square root of 1012000111 is about 31811.9491858012. The cubic root of 1012000111 is about 1003.9841425277.

Adding to 1012000111 its reverse (1110002101), we get a palindrome (2122002212).

The spelling of 1012000111 in words is "one billion, twelve million, one hundred eleven", and thus it is an aban number.