Base | Representation |
---|---|
bin | 1001001101000011111110… |
… | …1010110000001000111011 |
3 | 1022211110111222022212202112 |
4 | 2103100333222300020323 |
5 | 2311301240321334321 |
6 | 33305022515522535 |
7 | 2063101211136125 |
oct | 223207752601073 |
9 | 38743458285675 |
10 | 10120011121211 |
11 | 32519664a4722 |
12 | 11753ab2b944b |
13 | 58540b737894 |
14 | 26db4db2c215 |
15 | 1283a0d93a5b |
hex | 9343fab023b |
10120011121211 has 2 divisors, whose sum is σ = 10120011121212. Its totient is φ = 10120011121210.
The previous prime is 10120011121177. The next prime is 10120011121217. The reversal of 10120011121211 is 11212111002101.
10120011121211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10120011121211 - 210 = 10120011120187 is a prime.
It is not a weakly prime, because it can be changed into another prime (10120011121217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060005560605 + 5060005560606.
It is an arithmetic number, because the mean of its divisors is an integer number (5060005560606).
Almost surely, 210120011121211 is an apocalyptic number.
10120011121211 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120011121211 is an equidigital number, since it uses as much as digits as its factorization.
10120011121211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 10120011121211 its reverse (11212111002101), we get a palindrome (21332122123312).
The spelling of 10120011121211 in words is "ten trillion, one hundred twenty billion, eleven million, one hundred twenty-one thousand, two hundred eleven".
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