1012003100113 has 2 divisors, whose sum is σ = 1012003100114. Its totient is φ = 1012003100112.

The previous prime is 1012003100033. The next prime is 1012003100117. The reversal of 1012003100113 is 3110013002101.

1012003100113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1004990210064 + 7012890049 = 1002492^2 + 83743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012003100113 - 2¹³ = 1012003091921 is a prime.

It is a super-2 number, since 2×1012003100113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1012003100093 and 1012003100102.

It is not a weakly prime, because it can be changed into another prime (1012003100117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506001550056 + 506001550057.

It is an arithmetic number, because the mean of its divisors is an integer number (506001550057).

Almost surely, 2^{1012003100113} is an apocalyptic number.

It is an amenable number.

1012003100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012003100113 is an equidigital number, since it uses as much as digits as its factorization.

1012003100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1012003100113 its reverse (3110013002101), we get a palindrome (4122016102214).

The spelling of 1012003100113 in words is "one trillion, twelve billion, three million, one hundred thousand, one hundred thirteen".