101201102122021 has 4 divisors (see below), whose sum is σ = 110401202314944. Its totient is φ = 92001001929100.

The previous prime is 101201102122013. The next prime is 101201102122051. The reversal of 101201102122021 is 120221201102101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 101201102122021 - 2³ = 101201102122013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101201102121986 and 101201102122004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101201102122051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4600050096445 + ... + 4600050096466.

It is an arithmetic number, because the mean of its divisors is an integer number (27600300578736).

Almost surely, 2^{101201102122021} is an apocalyptic number.

101201102122021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

101201102122021 is a deficient number, since it is larger than the sum of its proper divisors (9200100192923).

101201102122021 is an equidigital number, since it uses as much as digits as its factorization.

101201102122021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9200100192922.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 101201102122021 its reverse (120221201102101), we get a palindrome (221422303224122).

The spelling of 101201102122021 in words is "one hundred one trillion, two hundred one billion, one hundred two million, one hundred twenty-two thousand, twenty-one".