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10120120101120 = 283519917877411
BaseRepresentation
bin1001001101000100011000…
…1010011110100100000000
31022211110210120101122002110
42103101012022132210000
52311302001221213440
633305041411415320
72063104003351611
oct223210612364400
938743716348073
1010120120101120
113251a11a69967
12117541b8b4540
135854281a3833
1426db603b9c08
151283aa71e080
hex9344629e900

10120120101120 has 288 divisors, whose sum is σ = 32506114636800. Its totient is φ = 2683272683520.

The previous prime is 10120120101107. The next prime is 10120120101131. The reversal of 10120120101120 is 2110102102101.

It is a super-2 number, since 2×101201201011202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 10120120101096 and 10120120101105.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1365550215 + ... + 1365557625.

It is an arithmetic number, because the mean of its divisors is an integer number (112868453600).

Almost surely, 210120120101120 is an apocalyptic number.

10120120101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10120120101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16253057318400).

10120120101120 is an abundant number, since it is smaller than the sum of its proper divisors (22385994535680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10120120101120 is a wasteful number, since it uses less digits than its factorization.

10120120101120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9421 (or 9407 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 10120120101120 its reverse (2110102102101), we get a palindrome (12230222203221).

The spelling of 10120120101120 in words is "ten trillion, one hundred twenty billion, one hundred twenty million, one hundred one thousand, one hundred twenty".