10120121311 has 4 divisors (see below), whose sum is σ = 10214701992. Its totient is φ = 10025540632.

The previous prime is 10120121309. The next prime is 10120121317. The reversal of 10120121311 is 11312102101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10120121311 - 2¹ = 10120121309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10120121291 and 10120121300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10120121317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47290180 + ... + 47290393.

It is an arithmetic number, because the mean of its divisors is an integer number (2553675498).

Almost surely, 2^10120121311 is an apocalyptic number.

10120121311 is a deficient number, since it is larger than the sum of its proper divisors (94580681).

10120121311 is an equidigital number, since it uses as much as digits as its factorization.

10120121311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94580680.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10120121311 its reverse (11312102101), we get a palindrome (21432223412).

The spelling of 10120121311 in words is "ten billion, one hundred twenty million, one hundred twenty-one thousand, three hundred eleven".