Base | Representation |
---|---|
bin | 10111000000101010111110… |
… | …010111110001101000111011 |
3 | 111021022202000120010021220101 |
4 | 113000222332113301220323 |
5 | 101231040041103111102 |
6 | 555123110125140231 |
7 | 30213355260041404 |
oct | 2700527627615073 |
9 | 437282016107811 |
10 | 101201213332027 |
11 | 2a278214685606 |
12 | b4255816ba677 |
13 | 4461305c124a3 |
14 | 1adc24453a9ab |
15 | ba7720c7ae87 |
hex | 5c0abe5f1a3b |
101201213332027 has 2 divisors, whose sum is σ = 101201213332028. Its totient is φ = 101201213332026.
The previous prime is 101201213332003. The next prime is 101201213332069. The reversal of 101201213332027 is 720233312102101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201213332027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101201213331986 and 101201213332004.
It is not a weakly prime, because it can be changed into another prime (101201213332097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600606666013 + 50600606666014.
It is an arithmetic number, because the mean of its divisors is an integer number (50600606666014).
Almost surely, 2101201213332027 is an apocalyptic number.
101201213332027 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201213332027 is an equidigital number, since it uses as much as digits as its factorization.
101201213332027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 101201213332027 its reverse (720233312102101), we get a palindrome (821434525434128).
The spelling of 101201213332027 in words is "one hundred one trillion, two hundred one billion, two hundred thirteen million, three hundred thirty-two thousand, twenty-seven".
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