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101201221111 = 674331500767
BaseRepresentation
bin101111001000000010…
…0000001010111110111
3100200012212221200211111
41132100010001113313
53124230003033421
6114254033215451
710211601120604
oct1362004012767
9320185850744
10101201221111
1139a124a6321
1217744101587
13970a640973
144c807cb6ab
152974916ee1
hex17901015f7

101201221111 has 4 divisors (see below), whose sum is σ = 101202789312. Its totient is φ = 101199652912.

The previous prime is 101201221103. The next prime is 101201221123. The reversal of 101201221111 is 111122102101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101201221111 - 23 = 101201221103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101201221091 and 101201221100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101201221181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 682951 + ... + 817816.

It is an arithmetic number, because the mean of its divisors is an integer number (25300697328).

Almost surely, 2101201221111 is an apocalyptic number.

101201221111 is a deficient number, since it is larger than the sum of its proper divisors (1568201).

101201221111 is an equidigital number, since it uses as much as digits as its factorization.

101201221111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1568200.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101201221111 its reverse (111122102101), we get a palindrome (212323323212).

The spelling of 101201221111 in words is "one hundred one billion, two hundred one million, two hundred twenty-one thousand, one hundred eleven".

Divisors: 1 67433 1500767 101201221111