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101201310033 = 3174011938611
BaseRepresentation
bin101111001000000010…
…0010111000101010001
3100200012220010012210220
41132100010113011101
53124230013410113
6114254035143253
710211601641055
oct1362004270521
9320186105726
10101201310033
1139a1255710a
1217744144b29
13970a672295
144c80811c65
152974933523
hex1790117151

101201310033 has 8 divisors (see below), whose sum is σ = 134942904096. Its totient is φ = 67463628000.

The previous prime is 101201309981. The next prime is 101201310071. The reversal of 101201310033 is 330013102101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101201310033 - 26 = 101201309969 is a prime.

It is a super-2 number, since 2×1012013100332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101201309994 and 101201310021.

It is not an unprimeable number, because it can be changed into a prime (101201318033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 917103 + ... + 1021508.

It is an arithmetic number, because the mean of its divisors is an integer number (16867863012).

Almost surely, 2101201310033 is an apocalyptic number.

It is an amenable number.

101201310033 is a deficient number, since it is larger than the sum of its proper divisors (33741594063).

101201310033 is a wasteful number, since it uses less digits than its factorization.

101201310033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1956015.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 101201310033 its reverse (330013102101), we get a palindrome (431214412134).

The spelling of 101201310033 in words is "one hundred one billion, two hundred one million, three hundred ten thousand, thirty-three".

Divisors: 1 3 17401 52203 1938611 5815833 33733770011 101201310033