Base | Representation |
---|---|
bin | 101111001000000010… |
… | …0010111000101110111 |
3 | 100200012220010012212022 |
4 | 1132100010113011313 |
5 | 3124230013410241 |
6 | 114254035143355 |
7 | 10211601641141 |
oct | 1362004270567 |
9 | 320186105768 |
10 | 101201310071 |
11 | 39a12557144 |
12 | 17744144b5b |
13 | 970a6722c4 |
14 | 4c80811c91 |
15 | 297493354b |
hex | 1790117177 |
101201310071 has 2 divisors, whose sum is σ = 101201310072. Its totient is φ = 101201310070.
The previous prime is 101201309981. The next prime is 101201310101. The reversal of 101201310071 is 170013102101.
It is a strong prime.
It is an emirp because it is prime and its reverse (170013102101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201310071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101201310571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600655035 + 50600655036.
It is an arithmetic number, because the mean of its divisors is an integer number (50600655036).
Almost surely, 2101201310071 is an apocalyptic number.
101201310071 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201310071 is an equidigital number, since it uses as much as digits as its factorization.
101201310071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
Adding to 101201310071 its reverse (170013102101), we get a palindrome (271214412172).
The spelling of 101201310071 in words is "one hundred one billion, two hundred one million, three hundred ten thousand, seventy-one".
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