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114254035143253 is a prime number
BaseRepresentation
bin11001111110100111010111…
…001011011100101001010101
3112222112120122011011212002121
4121332213113023130221111
5104433414230444041003
61042555325032335541
733031403333565535
oct3176472713345125
9488476564155077
10114254035143253
113344a956272945
12109932452445b1
134b9a1561334b5
14202dcd39534c5
15d3202289ecbd
hex67e9d72dca55

114254035143253 has 2 divisors, whose sum is σ = 114254035143254. Its totient is φ = 114254035143252.

The previous prime is 114254035143239. The next prime is 114254035143263. The reversal of 114254035143253 is 352341530452411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81928692793809 + 32325342349444 = 9051447^2 + 5685538^2 .

It is a cyclic number.

It is not a de Polignac number, because 114254035143253 - 213 = 114254035135061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114254035143263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127017571626 + 57127017571627.

It is an arithmetic number, because the mean of its divisors is an integer number (57127017571627).

Almost surely, 2114254035143253 is an apocalyptic number.

It is an amenable number.

114254035143253 is a deficient number, since it is larger than the sum of its proper divisors (1).

114254035143253 is an equidigital number, since it uses as much as digits as its factorization.

114254035143253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 114254035143253 its reverse (352341530452411), we get a palindrome (466595565595664).

The spelling of 114254035143253 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty-five million, one hundred forty-three thousand, two hundred fifty-three".