Base | Representation |
---|---|
bin | 10111000000101011000100… |
… | …101111100011110010110011 |
3 | 111021022202022000021021110001 |
4 | 113000223010233203302303 |
5 | 101231040300434330232 |
6 | 555123124504250431 |
7 | 30213361025463451 |
oct | 2700530457436263 |
9 | 437282260237401 |
10 | 101201320230067 |
11 | 2a278269a586a2 |
12 | b4255b1470a17 |
13 | 44613220cc975 |
14 | 1adc2548059d1 |
15 | ba772a3446e7 |
hex | 5c0ac4be3cb3 |
101201320230067 has 2 divisors, whose sum is σ = 101201320230068. Its totient is φ = 101201320230066.
The previous prime is 101201320230011. The next prime is 101201320230077. The reversal of 101201320230067 is 760032023102101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201320230067 is a prime.
It is a super-4 number, since 4×1012013202300674 (a number of 57 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (101201320230077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600660115033 + 50600660115034.
It is an arithmetic number, because the mean of its divisors is an integer number (50600660115034).
Almost surely, 2101201320230067 is an apocalyptic number.
101201320230067 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201320230067 is an equidigital number, since it uses as much as digits as its factorization.
101201320230067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 101201320230067 its reverse (760032023102101), we get a palindrome (861233343332168).
The spelling of 101201320230067 in words is "one hundred one trillion, two hundred one billion, three hundred twenty million, two hundred thirty thousand, sixty-seven".
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