1012013323 has 4 divisors (see below), whose sum is σ = 1031107968. Its totient is φ = 992918680.

The previous prime is 1012013311. The next prime is 1012013333. The reversal of 1012013323 is 3233102101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3233102101 = 2437 ⋅1326673.

It is a cyclic number.

It is not a de Polignac number, because 1012013323 - 2¹³ = 1012005131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012013297 and 1012013306.

It is not an unprimeable number, because it can be changed into a prime (1012013333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9547243 + ... + 9547348.

It is an arithmetic number, because the mean of its divisors is an integer number (257776992).

Almost surely, 2^1012013323 is an apocalyptic number.

1012013323 is a deficient number, since it is larger than the sum of its proper divisors (19094645).

1012013323 is an equidigital number, since it uses as much as digits as its factorization.

1012013323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19094644.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 1012013323 is about 31812.1568429429. The cubic root of 1012013323 is about 1003.9885116250.

Adding to 1012013323 its reverse (3233102101), we get a palindrome (4245115424).

The spelling of 1012013323 in words is "one billion, twelve million, thirteen thousand, three hundred twenty-three".