1012013311 has 2 divisors, whose sum is σ = 1012013312. Its totient is φ = 1012013310.

The previous prime is 1012013293. The next prime is 1012013333. The reversal of 1012013311 is 1133102101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1012013311 - 2⁵ = 1012013279 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012013291 and 1012013300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012013341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006655 + 506006656.

It is an arithmetic number, because the mean of its divisors is an integer number (506006656).

Almost surely, 2^1012013311 is an apocalyptic number.

1012013311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012013311 is an equidigital number, since it uses as much as digits as its factorization.

1012013311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1012013311 is about 31812.1566543358. The cubic root of 1012013311 is about 1003.9885076567.

Adding to 1012013311 its reverse (1133102101), we get a palindrome (2145115412).

The spelling of 1012013311 in words is "one billion, twelve million, thirteen thousand, three hundred eleven".