Base | Representation |
---|---|
bin | 101111001000000011… |
… | …1011011000111101010 |
3 | 100200012221122000021111 |
4 | 1132100013123013222 |
5 | 3124230220104002 |
6 | 114254104300534 |
7 | 10211611524064 |
oct | 1362007330752 |
9 | 320187560244 |
10 | 101202113002 |
11 | 39a12a55421 |
12 | 1774447174a |
13 | 970a893903 |
14 | 4c80980734 |
15 | 2974a413d7 |
hex | 17901db1ea |
101202113002 has 4 divisors (see below), whose sum is σ = 151803169506. Its totient is φ = 50601056500.
The previous prime is 101202112997. The next prime is 101202113011. The reversal of 101202113002 is 200311202101.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 98306704521 + 2895408481 = 313539^2 + 53809^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25300528249 + ... + 25300528252.
Almost surely, 2101202113002 is an apocalyptic number.
101202113002 is a deficient number, since it is larger than the sum of its proper divisors (50601056504).
101202113002 is an equidigital number, since it uses as much as digits as its factorization.
101202113002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50601056503.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 101202113002 its reverse (200311202101), we get a palindrome (301513315103).
The spelling of 101202113002 in words is "one hundred one billion, two hundred two million, one hundred thirteen thousand, two".
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