Base | Representation |
---|---|
bin | 10111000000101011110100… |
… | …011110101101100100000011 |
3 | 111021022211100211021200220021 |
4 | 113000223310132231210003 |
5 | 101231043421001320003 |
6 | 555123340154154311 |
7 | 30213416622104521 |
oct | 2700536436554403 |
9 | 437284324250807 |
10 | 101202121120003 |
11 | 2a278640047102 |
12 | b425795722997 |
13 | 446141c004937 |
14 | 1adc2ccd23311 |
15 | ba77757e52bd |
hex | 5c0af47ad903 |
101202121120003 has 2 divisors, whose sum is σ = 101202121120004. Its totient is φ = 101202121120002.
The previous prime is 101202121119959. The next prime is 101202121120013. The reversal of 101202121120003 is 300021121202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202121120003 - 225 = 101202087565571 is a prime.
It is not a weakly prime, because it can be changed into another prime (101202121120013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601060560001 + 50601060560002.
It is an arithmetic number, because the mean of its divisors is an integer number (50601060560002).
Almost surely, 2101202121120003 is an apocalyptic number.
101202121120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202121120003 is an equidigital number, since it uses as much as digits as its factorization.
101202121120003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 101202121120003 its reverse (300021121202101), we get a palindrome (401223242322104).
The spelling of 101202121120003 in words is "one hundred one trillion, two hundred two billion, one hundred twenty-one million, one hundred twenty thousand, three".
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