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10120221341 = 34731679209
BaseRepresentation
bin10010110110011011…
…00101001010011101
3222010021222111210122
421123031211022131
5131211234040331
64352115244325
7505534314326
oct113315451235
928107874718
1010120221341
11432366809a
121b652a96a5
13c53891069
146c00d944d
153e370917b
hex25b36529d

10120221341 has 8 divisors (see below), whose sum is σ = 10153693440. Its totient is φ = 10086774688.

The previous prime is 10120221299. The next prime is 10120221383. The reversal of 10120221341 is 14312202101.

It is an interprime number because it is at equal distance from previous prime (10120221299) and next prime (10120221383).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10120221341 - 214 = 10120204957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10120223341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1094345 + ... + 1103553.

It is an arithmetic number, because the mean of its divisors is an integer number (1269211680).

Almost surely, 210120221341 is an apocalyptic number.

It is an amenable number.

10120221341 is a deficient number, since it is larger than the sum of its proper divisors (33472099).

10120221341 is an equidigital number, since it uses as much as digits as its factorization.

10120221341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12723.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10120221341 its reverse (14312202101), we get a palindrome (24432423442).

The spelling of 10120221341 in words is "ten billion, one hundred twenty million, two hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 347 3167 9209 1098949 3195523 29164903 10120221341