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101202220013 = 739831410307
BaseRepresentation
bin101111001000000011…
…1110101001111101101
3100200012221211110001212
41132100013311033231
53124230232020023
6114254110444205
710211612451056
oct1362007651755
9320187743055
10101202220013
1139a13018864
1217744503665
13970a90052b
144c809ab72d
152974a62e78
hex17901f53ed

101202220013 has 8 divisors (see below), whose sum is σ = 102692987328. Its totient is φ = 99714275424.

The previous prime is 101202220001. The next prime is 101202220019. The reversal of 101202220013 is 310022202101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101202220013 - 28 = 101202219757 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101202220013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101202220019) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 633395 + ... + 776912.

It is an arithmetic number, because the mean of its divisors is an integer number (12836623416).

Almost surely, 2101202220013 is an apocalyptic number.

It is an amenable number.

101202220013 is a deficient number, since it is larger than the sum of its proper divisors (1490767315).

101202220013 is an equidigital number, since it uses as much as digits as its factorization.

101202220013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1411363.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 101202220013 its reverse (310022202101), we get a palindrome (411224422114).

The spelling of 101202220013 in words is "one hundred one billion, two hundred two million, two hundred twenty thousand, thirteen".

Divisors: 1 73 983 71759 1410307 102952411 1386331781 101202220013