Base | Representation |
---|---|
bin | 1001001101000100110000… |
… | …1111010001000111001011 |
3 | 1022211111001200011122120101 |
4 | 2103101030033101013023 |
5 | 2311302203314120133 |
6 | 33305055452110231 |
7 | 2063106351555412 |
oct | 223211417210713 |
9 | 38744050148511 |
10 | 10120222020043 |
11 | 3251a64551083 |
12 | 1175449a65377 |
13 | 5854433398a5 |
14 | 26db6db4a479 |
15 | 1283b465237d |
hex | 9344c3d11cb |
10120222020043 has 2 divisors, whose sum is σ = 10120222020044. Its totient is φ = 10120222020042.
The previous prime is 10120222020011. The next prime is 10120222020089. The reversal of 10120222020043 is 34002022202101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10120222020043 - 25 = 10120222020011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10120222020043.
It is not a weakly prime, because it can be changed into another prime (10120222024043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060111010021 + 5060111010022.
It is an arithmetic number, because the mean of its divisors is an integer number (5060111010022).
Almost surely, 210120222020043 is an apocalyptic number.
10120222020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120222020043 is an equidigital number, since it uses as much as digits as its factorization.
10120222020043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 10120222020043 its reverse (34002022202101), we get a palindrome (44122244222144).
The spelling of 10120222020043 in words is "ten trillion, one hundred twenty billion, two hundred twenty-two million, twenty thousand, forty-three".
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