Base | Representation |
---|---|
bin | 11101011101000010011… |
… | …10011001010101011001 |
3 | 10120202012120100111002221 |
4 | 32232201032121111121 |
5 | 113040110142020441 |
6 | 2052525552224041 |
7 | 133054565636323 |
oct | 16564116312531 |
9 | 3522176314087 |
10 | 1012022220121 |
11 | 360218183900 |
12 | 14417823b021 |
13 | 74582c10163 |
14 | 36da6daa613 |
15 | 1b4d1e258d1 |
hex | eba1399559 |
1012022220121 has 12 divisors (see below), whose sum is σ = 1112511630832. Its totient is φ = 919917999000.
The previous prime is 1012022220101. The next prime is 1012022220137. The reversal of 1012022220121 is 1210222202101.
It is a happy number.
It is not a de Polignac number, because 1012022220121 - 217 = 1012022089049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1012022220095 and 1012022220104.
It is not an unprimeable number, because it can be changed into a prime (1012022220101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 640006 + ... + 1560016.
Almost surely, 21012022220121 is an apocalyptic number.
1012022220121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1012022220121 is a deficient number, since it is larger than the sum of its proper divisors (100489410711).
1012022220121 is an equidigital number, since it uses as much as digits as its factorization.
1012022220121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 929124 (or 929113 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1012022220121 its reverse (1210222202101), we get a palindrome (2222244422222).
The spelling of 1012022220121 in words is "one trillion, twelve billion, twenty-two million, two hundred twenty thousand, one hundred twenty-one".
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