Base | Representation |
---|---|
bin | 10010110110011011… |
… | …01100111011011011 |
3 | 222010022001010102122 |
4 | 21123031230323123 |
5 | 131211241100042 |
6 | 4352120051455 |
7 | 505534506134 |
oct | 113315547333 |
9 | 28108033378 |
10 | 10120253147 |
11 | 4323689a84 |
12 | 1b65303b8b |
13 | c538a2694 |
14 | 6c0106c8b |
15 | 3e37137d2 |
hex | 25b36cedb |
10120253147 has 2 divisors, whose sum is σ = 10120253148. Its totient is φ = 10120253146.
The previous prime is 10120253113. The next prime is 10120253159. The reversal of 10120253147 is 74135202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10120253147 - 230 = 9046511323 is a prime.
It is not a weakly prime, because it can be changed into another prime (10120253107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060126573 + 5060126574.
It is an arithmetic number, because the mean of its divisors is an integer number (5060126574).
Almost surely, 210120253147 is an apocalyptic number.
10120253147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120253147 is an equidigital number, since it uses as much as digits as its factorization.
10120253147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 26.
Adding to 10120253147 its reverse (74135202101), we get a palindrome (84255455248).
The spelling of 10120253147 in words is "ten billion, one hundred twenty million, two hundred fifty-three thousand, one hundred forty-seven".
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