101210034342031 has 4 divisors (see below), whose sum is σ = 102720631869592. Its totient is φ = 99699436814472.

The previous prime is 101210034342013. The next prime is 101210034342049. The reversal of 101210034342031 is 130243430012101.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (101210034342013) and next prime (101210034342049).

It is a cyclic number.

It is not a de Polignac number, because 101210034342031 - 2¹⁷ = 101210034210959 is a prime.

It is a super-2 number, since 2×101210034342031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101210034341987 and 101210034342005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101210034342071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 755298763680 + ... + 755298763813.

It is an arithmetic number, because the mean of its divisors is an integer number (25680157967398).

Almost surely, 2^{101210034342031} is an apocalyptic number.

101210034342031 is a deficient number, since it is larger than the sum of its proper divisors (1510597527561).

101210034342031 is an equidigital number, since it uses as much as digits as its factorization.

101210034342031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1510597527560.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 101210034342031 its reverse (130243430012101), we get a palindrome (231453464354132).

The spelling of 101210034342031 in words is "one hundred one trillion, two hundred ten billion, thirty-four million, three hundred forty-two thousand, thirty-one".