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101210101112002 = 250605050556001
BaseRepresentation
bin10111000000110011010000…
…000111111101110011000010
3111021100120221222001021222111
4113000303100013331303002
5101231211241341041002
6555131140101125534
730214121440653361
oct2700632007756302
9437316858037874
10101210101112002
112a280a65599213
12b4272420b98aa
1344620c1360aac
141adc848a9d7d8
15ba7a9118c3d7
hex5c0cd01fdcc2

101210101112002 has 4 divisors (see below), whose sum is σ = 151815151668006. Its totient is φ = 50605050556000.

The previous prime is 101210101111991. The next prime is 101210101112137. The reversal of 101210101112002 is 200211101012101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 53833021735801 + 47377079376201 = 7337099^2 + 6883101^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25302525277999 + ... + 25302525278002.

Almost surely, 2101210101112002 is an apocalyptic number.

101210101112002 is a deficient number, since it is larger than the sum of its proper divisors (50605050556004).

101210101112002 is an equidigital number, since it uses as much as digits as its factorization.

101210101112002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50605050556003.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101210101112002 its reverse (200211101012101), we get a palindrome (301421202124103).

Subtracting 101210101112002 from its reverse (200211101012101), we obtain a palindrome (99000999900099).

The spelling of 101210101112002 in words is "one hundred one trillion, two hundred ten billion, one hundred one million, one hundred twelve thousand, two".

Divisors: 1 2 50605050556001 101210101112002