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1012120232113 is a prime number
BaseRepresentation
bin11101011101001110001…
…00010010000010110001
310120202110101210000021201
432232213010102002301
5113040310234411423
62052543413051201
7133060166011504
oct16564704220261
93522411700251
101012120232113
11360268537751
121441a5026b01
137459a308b13
1436db600113b
151b4da8362ad
hexeba71120b1

1012120232113 has 2 divisors, whose sum is σ = 1012120232114. Its totient is φ = 1012120232112.

The previous prime is 1012120232099. The next prime is 1012120232171. The reversal of 1012120232113 is 3112320212101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 737997828624 + 274122403489 = 859068^2 + 523567^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012120232113 - 221 = 1012118134961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1012120232173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506060116056 + 506060116057.

It is an arithmetic number, because the mean of its divisors is an integer number (506060116057).

Almost surely, 21012120232113 is an apocalyptic number.

It is an amenable number.

1012120232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012120232113 is an equidigital number, since it uses as much as digits as its factorization.

1012120232113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1012120232113 its reverse (3112320212101), we get a palindrome (4124440444214).

The spelling of 1012120232113 in words is "one trillion, twelve billion, one hundred twenty million, two hundred thirty-two thousand, one hundred thirteen".