1012130113 has 2 divisors, whose sum is σ = 1012130114. Its totient is φ = 1012130112.

The previous prime is 1012130083. The next prime is 1012130123. The reversal of 1012130113 is 3110312101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007237169 + 4892944 = 31737^2 + 2212^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012130113 - 2¹⁷ = 1011999041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012130093 and 1012130102.

It is not a weakly prime, because it can be changed into another prime (1012130123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506065056 + 506065057.

It is an arithmetic number, because the mean of its divisors is an integer number (506065057).

Almost surely, 2^1012130113 is an apocalyptic number.

It is an amenable number.

1012130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012130113 is an equidigital number, since it uses as much as digits as its factorization.

1012130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1012130113 is about 31813.9924090014. The cubic root of 1012130113 is about 1004.0271314420.

Adding to 1012130113 its reverse (3110312101), we get a palindrome (4122442214).

The spelling of 1012130113 in words is "one billion, twelve million, one hundred thirty thousand, one hundred thirteen".