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10122000113 is a prime number
BaseRepresentation
bin10010110110101000…
…10111011011110001
3222010102022212211002
421123110113123301
5131212213000423
64352221331345
7505555403261
oct113324273361
928112285732
1010122000113
114324672555
121b65a06b55
13c540648a4
146c043d7a1
153e395b228
hex25b5176f1

10122000113 has 2 divisors, whose sum is σ = 10122000114. Its totient is φ = 10122000112.

The previous prime is 10122000059. The next prime is 10122000197. The reversal of 10122000113 is 31100022101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10081766464 + 40233649 = 100408^2 + 6343^2 .

It is a cyclic number.

It is not a de Polignac number, because 10122000113 - 210 = 10121999089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10122000094 and 10122000103.

It is not a weakly prime, because it can be changed into another prime (10122000913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061000056 + 5061000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5061000057).

Almost surely, 210122000113 is an apocalyptic number.

It is an amenable number.

10122000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122000113 is an equidigital number, since it uses as much as digits as its factorization.

10122000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10122000113 its reverse (31100022101), we get a palindrome (41222022214).

The spelling of 10122000113 in words is "ten billion, one hundred twenty-two million, one hundred thirteen", and thus it is an aban number.