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101221024433 is a prime number
BaseRepresentation
bin101111001000100111…
…1100100001010110001
3100200021021012210212212
41132101033210022301
53124300040240213
6114300021501505
710212231340334
oct1362117441261
9320237183785
10101221024433
1139a226a1901
121774a871895
1397117856c9
144c832a461b
1529765299a8
hex17913e42b1

101221024433 has 2 divisors, whose sum is σ = 101221024434. Its totient is φ = 101221024432.

The previous prime is 101221024381. The next prime is 101221024469. The reversal of 101221024433 is 334420122101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53734948864 + 47486075569 = 231808^2 + 217913^2 .

It is a cyclic number.

It is not a de Polignac number, because 101221024433 - 218 = 101220762289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101221024399 and 101221024408.

It is not a weakly prime, because it can be changed into another prime (101221029433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610512216 + 50610512217.

It is an arithmetic number, because the mean of its divisors is an integer number (50610512217).

Almost surely, 2101221024433 is an apocalyptic number.

It is an amenable number.

101221024433 is a deficient number, since it is larger than the sum of its proper divisors (1).

101221024433 is an equidigital number, since it uses as much as digits as its factorization.

101221024433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 101221024433 its reverse (334420122101), we get a palindrome (435641146534).

The spelling of 101221024433 in words is "one hundred one billion, two hundred twenty-one million, twenty-four thousand, four hundred thirty-three".