Search a number
-
+
10122110401331 is a prime number
BaseRepresentation
bin1001001101001011110011…
…0010110111101100110011
31022211122221021111100201002
42103102330302313230303
52311320040230320311
633310011110432215
72063204221544255
oct223227462675463
938748837440632
1010122110401331
113252843490975
12117589636266b
13585684632b76
1426dcac86bcd5
1512847531793b
hex934bccb7b33

10122110401331 has 2 divisors, whose sum is σ = 10122110401332. Its totient is φ = 10122110401330.

The previous prime is 10122110401297. The next prime is 10122110401391. The reversal of 10122110401331 is 13310401122101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10122110401331 - 218 = 10122110139187 is a prime.

It is a super-2 number, since 2×101221104013312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10122110401391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061055200665 + 5061055200666.

It is an arithmetic number, because the mean of its divisors is an integer number (5061055200666).

Almost surely, 210122110401331 is an apocalyptic number.

10122110401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122110401331 is an equidigital number, since it uses as much as digits as its factorization.

10122110401331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10122110401331 its reverse (13310401122101), we get a palindrome (23432511523432).

The spelling of 10122110401331 in words is "ten trillion, one hundred twenty-two billion, one hundred ten million, four hundred one thousand, three hundred thirty-one".