Search a number
-
+
1012241420033 is a prime number
BaseRepresentation
bin11101011101011100100…
…10100100111100000001
310120202202211210222212012
432232232102210330001
5113041032300420113
62053003422342305
7133063200051164
oct16565622447401
93522684728765
101012241420033
1136031a98aa58
1214421972a995
13745b945a64c
1436dc8149adb
151b4e62c3aa8
hexebae4a4f01

1012241420033 has 2 divisors, whose sum is σ = 1012241420034. Its totient is φ = 1012241420032.

The previous prime is 1012241420027. The next prime is 1012241420053. The reversal of 1012241420033 is 3300241422101.

1012241420033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 664498868224 + 347742551809 = 815168^2 + 589697^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012241420033 - 24 = 1012241420017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012241419990 and 1012241420008.

It is not a weakly prime, because it can be changed into another prime (1012241420053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506120710016 + 506120710017.

It is an arithmetic number, because the mean of its divisors is an integer number (506120710017).

Almost surely, 21012241420033 is an apocalyptic number.

It is an amenable number.

1012241420033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012241420033 is an equidigital number, since it uses as much as digits as its factorization.

1012241420033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1012241420033 its reverse (3300241422101), we get a palindrome (4312482842134).

The spelling of 1012241420033 in words is "one trillion, twelve billion, two hundred forty-one million, four hundred twenty thousand, thirty-three".