10122434131 has 2 divisors, whose sum is σ = 10122434132. Its totient is φ = 10122434130.

The previous prime is 10122434107. The next prime is 10122434143. The reversal of 10122434131 is 13143422101.

It is a strong prime.

It is an emirp because it is prime and its reverse (13143422101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10122434131 - 2⁵ = 10122434099 is a prime.

It is a super-2 number, since 2×10122434131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10122434431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061217065 + 5061217066.

It is an arithmetic number, because the mean of its divisors is an integer number (5061217066).

Almost surely, 2^10122434131 is an apocalyptic number.

10122434131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122434131 is an equidigital number, since it uses as much as digits as its factorization.

10122434131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 10122434131 its reverse (13143422101), we get a palindrome (23265856232).

The spelling of 10122434131 in words is "ten billion, one hundred twenty-two million, four hundred thirty-four thousand, one hundred thirty-one".