Base | Representation |
---|---|
bin | 10010110110101100… |
… | …00010110100011011 |
3 | 222010110011020011211 |
4 | 21123112002310123 |
5 | 131212321034323 |
6 | 4352235003551 |
7 | 505562214526 |
oct | 113326026433 |
9 | 28113136154 |
10 | 10122439963 |
11 | 4324942a69 |
12 | 1b65b995b7 |
13 | c54189b5c |
14 | 6c0515bbd |
15 | 3e39e670d |
hex | 25b582d1b |
10122439963 has 2 divisors, whose sum is σ = 10122439964. Its totient is φ = 10122439962.
The previous prime is 10122439933. The next prime is 10122439973. The reversal of 10122439963 is 36993422101.
10122439963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10122439963 - 233 = 1532505371 is a prime.
It is not a weakly prime, because it can be changed into another prime (10122439903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061219981 + 5061219982.
It is an arithmetic number, because the mean of its divisors is an integer number (5061219982).
Almost surely, 210122439963 is an apocalyptic number.
10122439963 is a deficient number, since it is larger than the sum of its proper divisors (1).
10122439963 is an equidigital number, since it uses as much as digits as its factorization.
10122439963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 40.
The spelling of 10122439963 in words is "ten billion, one hundred twenty-two million, four hundred thirty-nine thousand, nine hundred sixty-three".
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