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10123300130011 is a prime number
BaseRepresentation
bin1001001101010000001110…
…1101010100110011011011
31022211210000012011211122021
42103110003231110303123
52311330004313130021
633310325130435311
72063245546223065
oct223240355246333
938753005154567
1010123300130011
1132532a4011712
121175b68892b37
13585813c6c133
1426dd82886735
151284e49c4c41
hex93503b54cdb

10123300130011 has 2 divisors, whose sum is σ = 10123300130012. Its totient is φ = 10123300130010.

The previous prime is 10123300129993. The next prime is 10123300130071. The reversal of 10123300130011 is 11003100332101.

10123300130011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11003100332101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10123300130011 - 217 = 10123299998939 is a prime.

It is not a weakly prime, because it can be changed into another prime (10123300130071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061650065005 + 5061650065006.

It is an arithmetic number, because the mean of its divisors is an integer number (5061650065006).

Almost surely, 210123300130011 is an apocalyptic number.

10123300130011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10123300130011 is an equidigital number, since it uses as much as digits as its factorization.

10123300130011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10123300130011 its reverse (11003100332101), we get a palindrome (21126400462112).

The spelling of 10123300130011 in words is "ten trillion, one hundred twenty-three billion, three hundred million, one hundred thirty thousand, eleven".