10123302042133 has 4 divisors (see below), whose sum is σ = 11569488048160. Its totient is φ = 8677116036108.

The previous prime is 10123302042131. The next prime is 10123302042143. The reversal of 10123302042133 is 33124020332101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10123302042133 - 2¹ = 10123302042131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10123302042098 and 10123302042107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10123302042131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723093003003 + ... + 723093003016.

It is an arithmetic number, because the mean of its divisors is an integer number (2892372012040).

Almost surely, 2^{10123302042133} is an apocalyptic number.

It is an amenable number.

10123302042133 is a deficient number, since it is larger than the sum of its proper divisors (1446186006027).

10123302042133 is an equidigital number, since it uses as much as digits as its factorization.

10123302042133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1446186006026.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10123302042133 its reverse (33124020332101), we get a palindrome (43247322374234).

The spelling of 10123302042133 in words is "ten trillion, one hundred twenty-three billion, three hundred two million, forty-two thousand, one hundred thirty-three".