Base | Representation |
---|---|
bin | 111100010110100… |
… | …010011010111001 |
3 | 2121120021102021201 |
4 | 330112202122321 |
5 | 4033202303423 |
6 | 244250134201 |
7 | 34043312623 |
oct | 7426423271 |
9 | 2546242251 |
10 | 1012541113 |
11 | 47a60a141 |
12 | 243121361 |
13 | 131a0b56c |
14 | 98693c13 |
15 | 5dd5c2ad |
hex | 3c5a26b9 |
1012541113 has 2 divisors, whose sum is σ = 1012541114. Its totient is φ = 1012541112.
The previous prime is 1012541087. The next prime is 1012541197. The reversal of 1012541113 is 3111452101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 515607849 + 496933264 = 22707^2 + 22292^2 .
It is an emirp because it is prime and its reverse (3111452101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1012541113 - 29 = 1012540601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1012541713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506270556 + 506270557.
It is an arithmetic number, because the mean of its divisors is an integer number (506270557).
Almost surely, 21012541113 is an apocalyptic number.
It is an amenable number.
1012541113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012541113 is an equidigital number, since it uses as much as digits as its factorization.
1012541113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 19.
The square root of 1012541113 is about 31820.4511753055. The cubic root of 1012541113 is about 1004.1630162464.
Adding to 1012541113 its reverse (3111452101), we get a palindrome (4123993214).
The spelling of 1012541113 in words is "one billion, twelve million, five hundred forty-one thousand, one hundred thirteen".
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