Base | Representation |
---|---|
bin | 111100010110100… |
… | …010110000100001 |
3 | 2121120021111011222 |
4 | 330112202300201 |
5 | 4033202324442 |
6 | 244250144425 |
7 | 34043316641 |
oct | 7426426041 |
9 | 2546244158 |
10 | 1012542497 |
11 | 47a61018a |
12 | 243122115 |
13 | 131a0c095 |
14 | 98694521 |
15 | 5dd5c8d2 |
hex | 3c5a2c21 |
1012542497 has 2 divisors, whose sum is σ = 1012542498. Its totient is φ = 1012542496.
The previous prime is 1012542439. The next prime is 1012542523. The reversal of 1012542497 is 7942452101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 572214241 + 440328256 = 23921^2 + 20984^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012542497 - 28 = 1012542241 is a prime.
It is not a weakly prime, because it can be changed into another prime (1012542397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506271248 + 506271249.
It is an arithmetic number, because the mean of its divisors is an integer number (506271249).
Almost surely, 21012542497 is an apocalyptic number.
It is an amenable number.
1012542497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012542497 is an equidigital number, since it uses as much as digits as its factorization.
1012542497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
The square root of 1012542497 is about 31820.4729223184. The cubic root of 1012542497 is about 1004.1634737623.
Adding to 1012542497 its reverse (7942452101), we get a palindrome (8954994598).
The spelling of 1012542497 in words is "one billion, twelve million, five hundred forty-two thousand, four hundred ninety-seven".
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